20y^2-21y-5=0

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Solution for 20y^2-21y-5=0 equation:


Simplifying
20y2 + -21y + -5 = 0

Reorder the terms:
-5 + -21y + 20y2 = 0

Solving
-5 + -21y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -5y)(5 + -4y) = 0

Subproblem 1

Set the factor '(-1 + -5y)' equal to zero and attempt to solve: Simplifying -1 + -5y = 0 Solving -1 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5y = 0 + 1 -5y = 0 + 1 Combine like terms: 0 + 1 = 1 -5y = 1 Divide each side by '-5'. y = -0.2 Simplifying y = -0.2

Subproblem 2

Set the factor '(5 + -4y)' equal to zero and attempt to solve: Simplifying 5 + -4y = 0 Solving 5 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4y = 0 + -5 -4y = 0 + -5 Combine like terms: 0 + -5 = -5 -4y = -5 Divide each side by '-4'. y = 1.25 Simplifying y = 1.25

Solution

y = {-0.2, 1.25}

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